What is 1^{100}+2^3+1^{10}-3^2 ?

The solution to 1^{100}+2^3+1^{10}-3^2 is 1

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1^{100}+2^3+1^{10}-3^2

1^{100} + 2^{3} + 1^{10} - 3^{2}

1

Solution steps

1^{100} + 2^{3} + 1^{10} - 3^{2}

Follow the PEMDAS order of operations

Calculate exponents

1^{100} : 1

= 1 + 2^{3} + 1^{10} - 3^{2}

Calculate exponents

2^{3} : 8

= 1 + 8 + 1^{10} - 3^{2}

Calculate exponents

1^{10} : 1

= 1 + 8 + 1 - 3^{2}

Calculate exponents

3^{2} : 9

= 1 + 8 + 1 - 9

Add and subtract (left to right)

1 + 8 + 1 - 9 : 1

= 1

300 \div 5 (2 + 4) \div (7 - 1) \times 3

2 - 4 \times 3 + 12

10 - 2 [6 + (8 - 4)^{2}] \times 5

4003 - 3468 \div 34 + 104

- \frac{3}{2} \times 3 + 5