What is 4^2-2^3-(3-16\div 4-2+1) ?

The solution to 4^2-2^3-(3-16\div 4-2+1) is 10

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4^2-2^3-(3-16\div 4-2+1)

4^{2} - 2^{3} - (3 - 16 \div 4 - 2 + 1)

10

Solution steps

4^{2} - 2^{3} - (3 - 16 \div 4 - 2 + 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 16 \div 4 - 2 + 1) : - 2

3 - 16 \div 4 - 2 + 1

Multiply and divide (left to right)

16 \div 4 : 4

16 \div 4

16 \div 4 = 4

= 4

= 3 - 4 - 2 + 1

Add and subtract (left to right)

3 - 4 - 2 + 1 : - 2

3 - 4 - 2 + 1

3 - 4 = - 1

= - 1 - 2 + 1

- 1 - 2 = - 3

= - 3 + 1

- 3 + 1 = - 2

= - 2

= - 2

= 4^{2} - 2^{3} - (- 2)

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 - 2^{3} - (- 2)

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 16 - 8 - (- 2)

Add and subtract (left to right)

16 - 8 - (- 2) : 10

16 - 8 - (- 2)

16 - 8 = 8

= 8 - (- 2)

Apply rule

- (- a) = + a

- (- 2) = + 2

= 8 + 2

8 + 2 = 10

= 10

= 10

9^{2} \times 15

8 - 5 \times 3

\frac{5 - 3 \times 3 ^{2}}{2}

6^{2} (\frac{2}{5} + 5) - 3

[3 - (4 - 2^{3})^{2}]^{2}

What is 4^2-2^3-(3-16\div 4-2+1) ?
The solution to 4^2-2^3-(3-16\div 4-2+1) is 10