What is 6/2 \div (5+12-3)*4 ?

The solution to 6/2 \div (5+12-3)*4 is 6/7

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6/2 \div (5+12-3)*4

\frac{6}{2} \div (5 + 12 - 3) \cdot 4

\frac{6}{7}

Solution steps

\frac{6}{2} \div (5 + 12 - 3) \cdot 4

\frac{6}{2} = 3

Divide the numbers:

\frac{6}{2} = 3

3

= 3 \div (5 + 12 - 3) \cdot 4

Follow the PEMDAS order of operations

Calculate within parentheses

(5 + 12 - 3) : 14

5 + 12 - 3

Add and subtract (left to right)

5 + 12 = 17

= 17 - 3

17 - 3 = 14

= 14

= 3 \div 14 \cdot 4

Multiply and divide (left to right)

3 \div 14 \cdot 4 : \frac{6}{7}

3 \div 14 \cdot 4

3 \div 14 = \frac{3}{14}

= \frac{3}{14} \cdot 4

\frac{3}{14} 4 = \frac{6}{7}

\frac{3}{14} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= \frac{3}{14} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 4}{14 \cdot 1}

Cancel

\frac{3 \cdot 4}{14 \cdot 1} : \frac{6}{7}

\frac{3 \cdot 4}{14 \cdot 1}

Multiply the numbers:

14 \cdot 1 = 14

= \frac{3 \cdot 4}{14}

Factor the number:

4 = 2 \cdot 2

= \frac{3 \cdot 2 \cdot 2}{14}

Factor the number:

14 = 2 \cdot 7

= \frac{3 \cdot 2 \cdot 2}{2 \cdot 7}

Cancel the common factor:

2

= \frac{3 \cdot 2}{7}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{6}{7}

= \frac{6}{7}

= \frac{6}{7}

= \frac{6}{7}

6 + 3 (6) - 3 (7) - 3

\frac{5}{6} (3)^{5}

- 3 (- 3) + 2

\frac{1}{2} 2^{4} - \frac{3}{4} 2^{2}

\frac{2 ( 3 - 12 )}{9}