What is 5^2-2^3(-2)^2+6^0 ?

The solution to 5^2-2^3(-2)^2+6^0 is -6

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5^2-2^3(-2)^2+6^0

5^{2} - 2^{3} (- 2)^{2} + 6^{0}

- 6

Solution steps

5^{2} - 2^{3} (- 2)^{2} + 6^{0}

Follow the PEMDAS order of operations

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 25 - 2^{3} (- 2)^{2} + 6^{0}

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 25 - 8 (- 2)^{2} + 6^{0}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 25 - 8 \cdot 4 + 6^{0}

Calculate exponents

6^{0} : 1

6^{0}

6^{0} = 1

= 1

= 25 - 8 \cdot 4 + 1

Multiply and divide (left to right)

8 \cdot 4 : 32

8 \cdot 4

8 \cdot 4 = 32

= 32

= 25 - 32 + 1

Add and subtract (left to right)

25 - 32 + 1 : - 6

25 - 32 + 1

25 - 32 = - 7

= - 7 + 1

- 7 + 1 = - 6

= - 6

= - 6

- \frac{2}{3} (2) + 3

(- 1)^{2} - 7

5 \cdot 4 + 3

14/4 - (3/11 + 1/11 + 2111)

8 (- 2)^{2} - 27