What is 2^3+(-1)^{10}+(-3)^2 ?

The solution to 2^3+(-1)^{10}+(-3)^2 is 18

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2^3+(-1)^{10}+(-3)^2

2^{3} + (- 1)^{10} + (- 3)^{2}

18

Solution steps

2^{3} + (- 1)^{10} + (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 + (- 1)^{10} + (- 3)^{2}

Calculate exponents

(- 1)^{10} : 1

(- 1)^{10}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{10} = 1^{10} = 1

= 1

= 8 + 1 + (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 8 + 1 + 9

Add and subtract (left to right)

8 + 1 + 9 : 18

8 + 1 + 9

8 + 1 = 9

= 9 + 9

9 + 9 = 18

= 18

= 18

3 [- 3] + 8 [- 3]^{2} (5 [0]^{2} [- 3])

2 \cdot 3 - 5/7 + 3

\frac{( 6 \cdot 4 + 0 )}{5}

8 + 3 (16 - 2)

6 0^{2} + 3 2^{2}