What is 2\times 17/7-5 ?

The solution to 2\times 17/7-5 is -1/7

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2\times 17/7-5

2 \cdot \frac{17}{7} - 5

- \frac{1}{7}

Solution steps

2 \cdot \frac{17}{7} - 5

Follow the PEMDAS order of operations

Multiply and divide (left to right)

2 \cdot \frac{17}{7} : \frac{34}{7}

2 \cdot \frac{17}{7}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{17}{7}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 17}{1 \cdot 7}

Multiply the numbers:

2 \cdot 17 = 34

= \frac{34}{1 \cdot 7}

Multiply the numbers:

1 \cdot 7 = 7

= \frac{34}{7}

= \frac{34}{7} - 5

Add and subtract (left to right)

\frac{34}{7} - 5 : - \frac{1}{7}

\frac{34}{7} - 5

\frac{34}{7} - 5 = - \frac{1}{7}

\frac{34}{7} - 5

Convert element to fraction:

5 = \frac{5 \cdot 7}{7}

= - \frac{5 \cdot 7}{7} + \frac{34}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 5 \cdot 7 + 34}{7}

- 5 \cdot 7 + 34 = - 1

- 5 \cdot 7 + 34

Multiply the numbers:

5 \cdot 7 = 35

= - 35 + 34

Add/Subtract the numbers:

- 35 + 34 = - 1

= - 1

= \frac{- 1}{7}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{7}

= - \frac{1}{7}

= - \frac{1}{7}

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[(22 + 4)^{2} - 2 (19 + 3)^{2}]^{0}

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