What is ((6+1)^2-14)/5 ?

The solution to ((6+1)^2-14)/5 is 7

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((6+1)^2-14)/5

\frac{( 6 + 1 ) ^{2} - 14}{5}

7

Solution steps

\frac{( 6 + 1 ) ^{2} - 14}{5}

Solve

(6 + 1)^{2} - 14 : 35

Follow the PEMDAS order of operations

Calculate within parentheses

(6 + 1) : 7

6 + 1

6 + 1 = 7

= 7

= 7^{2} - 14

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 49 - 14

Add and subtract (left to right)

49 - 14 : 35

49 - 14

49 - 14 = 35

= 35

= 35

= \frac{35}{5}

Divide the numbers:

\frac{35}{5} = 7

= 7

10 \cdot 2^{2}

- 6 + 8 - 6

\frac{15 ( 15 - 69 )}{2}

- 5 (2)^{2} + 5 (2) + 5

16 \div (5^{2} - 21) + 10