What is 18\times 54-58\div 98-3\times 12 ?

The solution to 18\times 54-58\div 98-3\times 12 is 935 20/49

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18\times 54-58\div 98-3\times 12

18 \times 54 - 58 \div 98 - 3 \times 12

935 \frac{20}{49}

Solution steps

18 \times 54 - 58 \div 98 - 3 \times 12

Follow the PEMDAS order of operations

Multiply and divide (left to right)

18 \times 54 : 972

= 972 - 58 \div 98 - 3 \times 12

Multiply and divide (left to right)

58 \div 98 : \frac{58}{98}

= 972 - \frac{58}{98} - 3 \times 12

Multiply and divide (left to right)

3 \times 12 : 36

= 972 - \frac{58}{98} - 36

Add and subtract (left to right)

972 - \frac{58}{98} - 36 : \frac{45835}{49}

= \frac{45835}{49}

Convert improper fractions to mixed numbers:

\frac{45835}{49} = 935 \frac{20}{49}

= 935 \frac{20}{49}

0^{2} + 2

16 \div 4 (3 - 1)

(- 3)^{8} \div 3^{5}

1 2^{2} + 1 2^{2}

\frac{5}{12} + ((2) \div (\frac{4}{8}) - 3)

What is 18\times 54-58\div 98-3\times 12 ?
The solution to 18\times 54-58\div 98-3\times 12 is 935 20/49