What is 6\times (8-3+5)\div 10 ?

The solution to 6\times (8-3+5)\div 10 is 6

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6\times (8-3+5)\div 10

6 \times (8 - 3 + 5) \div 10

6

Solution steps

6 \times (8 - 3 + 5) \div 10

Follow the PEMDAS order of operations

Calculate within parentheses

(8 - 3 + 5) : 10

8 - 3 + 5

Add and subtract (left to right)

8 - 3 = 5

= 5 + 5

5 + 5 = 10

= 10

= 6 \times 10 \div 10

Multiply and divide (left to right)

6 \times 10 \div 10 : 6

6 \times 10 \div 10

6 \times 10 = 60

= 60 \div 10

60 \div 10 = 6

= 6

= 6

6 + 4 \div 2

0 - (- 21) \frac{2}{3}

- 30 + 10 - 5 + 7 - 15

60 - 50 \div 2 + 4

- 4 (6 - 8) - 3 (5 - 3)