What is -3(4)^2+6(4)+24 ?

The solution to -3(4)^2+6(4)+24 is 0

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-3(4)^2+6(4)+24

- 3 (4)^{2} + 6 (4) + 24

0

Solution steps

- 3 (4)^{2} + 6 (4) + 24

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= - 3 \cdot 16 + 6 (4) + 24

Multiply and divide (left to right)

- 3 \cdot 16 : - 48

- 3 \cdot 16

- 3 \cdot 16 = - 48

= - 48

= - 48 + 6 (4) + 24

Multiply and divide (left to right)

6 (4) : 24

6 (4)

Apply rule:

(a) = a

(4) = 4

= 6 \cdot 4

Multiply the numbers:

6 \cdot 4 = 24

= 24

= - 48 + 24 + 24

Add and subtract (left to right)

- 48 + 24 + 24 : 0

- 48 + 24 + 24

- 48 + 24 = - 24

= - 24 + 24

- 24 + 24 = 0

= 0

= 0

(1 - 41)^{3}

6 - 6 \times \frac{1}{3}

(30 + 7)^{2}

+ 7 - 3 + 5 + 2 - 4 + 6

\frac{9 ( 2 ) + 18}{12}