What is -1^2+(2\times (-1))-1 ?

The solution to -1^2+(2\times (-1))-1 is -4

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-1^2+(2\times (-1))-1

- 1^{2} + (2 \cdot (- 1)) - 1

- 4

Solution steps

- 1^{2} + (2 (- 1)) - 1

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \cdot (- 1)) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= - 1^{2} - 2 - 1

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= - 1 - 2 - 1

Add and subtract (left to right)

- 1 - 2 - 1 : - 4

- 1 - 2 - 1

- 1 - 2 = - 3

= - 3 - 1

- 3 - 1 = - 4

= - 4

= - 4

5 + 2 (- 1)

- 4 (0)^{2} + 6

5 \cdot 3 0^{2}

4 \frac{5}{3} - 2 + 2 \frac{4}{5}

\frac{1}{2} \cdot (- 2) + 2