What is (3\times 7+2\times 15)\times (81+4\times 20) ?

The solution to (3\times 7+2\times 15)\times (81+4\times 20) is 8211

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(3\times 7+2\times 15)\times (81+4\times 20)

(3 \cdot 7 + 2 \cdot 15) \cdot (81 + 4 \cdot 20)

8211

Solution steps

(3 \cdot 7 + 2 \cdot 15) (81 + 4 \cdot 20)

Follow the PEMDAS order of operations

Calculate within parentheses

(3 \cdot 7 + 2 \cdot 15) : 51

= 51 (81 + 4 \cdot 20)

Calculate within parentheses

(81 + 4 \cdot 20) : 161

= 51 \cdot 161

Multiply and divide (left to right)

51 \cdot 161 : 8211

= 8211

- 3 + 4 (- 2 (5))

5 + 3 \cdot (12 + 2)

15 - 4 (3 - 5)

10 - (- 5 + (- 7 + 5) - (- 2) - (- 8)) - (- 6)

6 \times 4 + 2 \times \frac{9}{3}

What is (3\times 7+2\times 15)\times (81+4\times 20) ?
The solution to (3\times 7+2\times 15)\times (81+4\times 20) is 8211