What is (5-3)^2+12-41 ?

The solution to (5-3)^2+12-41 is -25

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(5-3)^2+12-41

(5 - 3)^{2} + 12 - 41

- 25

Solution steps

(5 - 3)^{2} + 12 - 41

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 3) : 2

= 2^{2} + 12 - 41

Calculate exponents

2^{2} : 4

= 4 + 12 - 41

Add and subtract (left to right)

4 + 12 - 41 : - 25

= - 25

(15 - 3)^{2}

(- 3) - (+ 4) - (- 8)

3 \div 2 (3 + 3)

2^{3} - 2 - 6

\frac{1}{3} \times 12