What is (2-(3\times (3-6+7)^2-2\times 3)+5)\div 2 ?

The solution to (2-(3\times (3-6+7)^2-2\times 3)+5)\div 2 is -17 1/2

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(2-(3\times (3-6+7)^2-2\times 3)+5)\div 2

(2 - (3 \times (3 - 6 + 7)^{2} - 2 \times 3) + 5) \div 2

- 17 \frac{1}{2}

Solution steps

(2 - (3 \times (3 - 6 + 7)^{2} - 2 \times 3) + 5) \div 2

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - (3 \times (3 - 6 + 7)^{2} - 2 \times 3) + 5) : - 35

= - 35 \div 2

Multiply and divide (left to right)

- 35 \div 2 : \frac{- 35}{2}

= \frac{- 35}{2}

Simplify

\frac{- 35}{2} : - 17 \frac{1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{35}{2}

Convert improper fractions to mixed numbers:

\frac{35}{2} = 17 \frac{1}{2}

= - 17 \frac{1}{2}

\frac{3}{8} + \frac{4}{8} \div 5 + \frac{1}{3}

60 - \frac{1}{2} (8)^{2}

(- 5 (3) + 6) (3 (3)^{2} - 3 (3) + 2)

(6)^{2} + 8 (6) - 3

8 - 2 (- 4) + 5

What is (2-(3\times (3-6+7)^2-2\times 3)+5)\div 2 ?
The solution to (2-(3\times (3-6+7)^2-2\times 3)+5)\div 2 is -17 1/2