The solution to -(3-2)^2+6 is 5

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-(3-2)^2+6

Solution

- (3 - 2)^{2} + 6

5

Solution steps

- (3 - 2)^{2} + 6

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 2) : 1

3 - 2

3 - 2 = 1

= 1

= - 1^{2} + 6

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= - 1 + 6

Add and subtract (left to right)

- 1 + 6 : 5

- 1 + 6

- 1 + 6 = 5

= 5

= 5

\frac{- 18 - 16}{- 18 - 18}

63 \div 7 \times 3 - 4

- 3 + 7 + 4^{2} + 6 - 3 \times 4 \div 2

(2 - 3) (2 - 3)

- (2)^{2} + 6 (2)