What is 3^2+(-2)^3-5^2+(-4) ?

The solution to 3^2+(-2)^3-5^2+(-4) is -28

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3^2+(-2)^3-5^2+(-4)

3^{2} + (- 2)^{3} - 5^{2} + (- 4)

- 28

Solution steps

3^{2} + (- 2)^{3} - 5^{2} + (- 4)

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 + (- 2)^{3} - 5^{2} + (- 4)

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 9 - 8 - 5^{2} + (- 4)

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 9 - 8 - 5^{2} + (- 4)

Add and subtract (left to right)

9 - 8 - 5^{2} + (- 4) : - 28

9 - 8 - 5^{2} + (- 4)

9 - 8 = 1

= 1 - 5^{2} + (- 4)

1 - 5^{2} = - 24

= - 24 + (- 4)

Apply rule

+ (- a) = - a

+ (- 4) = - 4

= - 24 - 4

- 24 - 4 = - 28

= - 28

= - 28

(779)^{2} - 608401

(6 \times 3^{2}) \div 9

\frac{3}{4} \cdot 8 - 2

- 2 (0)^{2} + 4 (0) + 1

- 2 (0)^{2} + 4 (0) + 3