What is [36-(4+6)+2]-[1+24+3] ?

The solution to [36-(4+6)+2]-[1+24+3] is 0

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[36-(4+6)+2]-[1+24+3]

[36 - (4 + 6) + 2] - [1 + 24 + 3]

0

Solution steps

[36 - (4 + 6) + 2] - [1 + 24 + 3]

Follow the PEMDAS order of operations

Calculate within parentheses

[36 - (4 + 6) + 2] : 28

= 28 - [1 + 24 + 3]

Calculate within parentheses

[1 + 24 + 3] : 28

= 28 - 28

Add and subtract (left to right)

28 - 28 : 0

= 0

- \frac{2}{5} (- 2) - 2

- 2^{3} + 6 (- 2)^{2} + 13 (- 2) + 10

1^{0} - 1^{100}

(150 - 60 \div 3) - 9 \times 6 - (24 \div 3 \times 4)

1 5^{2} \div 3^{2}