What is 32-6+4-(3^2-4+8^2)^2 ?

The solution to 32-6+4-(3^2-4+8^2)^2 is -4731

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32-6+4-(3^2-4+8^2)^2

32 - 6 + 4 - (3^{2} - 4 + 8^{2})^{2}

- 4731

Solution steps

32 - 6 + 4 - (3^{2} - 4 + 8^{2})^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{2} - 4 + 8^{2}) : 69

= 32 - 6 + 4 - 6 9^{2}

Calculate exponents

6 9^{2} : 4761

= 32 - 6 + 4 - 4761

Add and subtract (left to right)

32 - 6 + 4 - 4761 : - 4731

= - 4731

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8 (1)^{2} - 7 (1) + 8

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