What is 2[4-(-3+7)]^2 ?

The solution to 2[4-(-3+7)]^2 is 0

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2[4-(-3+7)]^2

2 [4 - (- 3 + 7)]^{2}

0

Solution steps

2 [4 - (- 3 + 7)]^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

[4 - (- 3 + 7)] : 0

= 2 \cdot 0^{2}

Calculate exponents

0^{2} : 0

= 2 \cdot 0

Multiply and divide (left to right)

2 \cdot 0 : 0

= 0

(5 \times 1 0^{3}) / (- 6 \times 1 0^{1})

- 5 + 8 + 7 - 9 - 8 + 17

2 \cdot (2)^{2}

\frac{5}{5} \times 5 (\frac{10}{5} + 2)

- 2^{2} + 16