What is (1+5/3)\times (-8)\div 7 ?

The solution to (1+5/3)\times (-8)\div 7 is -64/21

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(1+5/3)\times (-8)\div 7

(1 + \frac{5}{3}) \times (- 8) \div 7

- \frac{64}{21}

Solution steps

(1 + \frac{5}{3}) \times (- 8) \div 7

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + \frac{5}{3}) : \frac{8}{3}

1 + \frac{5}{3}

1 + \frac{5}{3} = \frac{8}{3}

1 + \frac{5}{3}

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= \frac{1 \cdot 3}{3} + \frac{5}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 3 + 5}{3}

1 \cdot 3 + 5 = 8

1 \cdot 3 + 5

Multiply the numbers:

1 \cdot 3 = 3

= 3 + 5

Add the numbers:

3 + 5 = 8

= 8

= \frac{8}{3}

= \frac{8}{3}

= \frac{8}{3} \times (- 8) \div 7

Multiply and divide (left to right)

\frac{8}{3} \times (- 8) \div 7 : - \frac{64}{21}

\frac{8}{3} \times (- 8) \div 7

\frac{8}{3} \times (- 8) = - \frac{64}{3}

\frac{8}{3} \times (- 8)

Apply rule

a \times (- b) = - a \times b

\frac{8}{3} \times (- 8) = - \frac{8}{3} \times 8

Convert element to fraction:

8 = \frac{8}{1}

= - \frac{8}{3} \cdot \frac{8}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{8}{3} \cdot \frac{8}{1} = \frac{8 \cdot 8}{3 \cdot 1}

= - \frac{8 \cdot 8}{3 \cdot 1}

Multiply the numbers:

8 \cdot 8 = 64

= - \frac{64}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= - \frac{64}{3}

= - \frac{64}{3} \div 7

- \frac{64}{3} \div 7 = - \frac{64}{21}

- \frac{64}{3} \div 7

Convert element to fraction:

7 = \frac{7}{1}

= - \frac{64}{3} \div \frac{7}{1}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= - \frac{64}{3} \cdot \frac{1}{7}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{64 \cdot 1}{3 \cdot 7}

Multiply the numbers:

64 \cdot 1 = 64

= - \frac{64}{3 \cdot 7}

Multiply the numbers:

3 \cdot 7 = 21

= - \frac{64}{21}

= - \frac{64}{21}

= - \frac{64}{21}

3^{3} + 2 (3)^{2} - 8 (3) - 21

- \frac{1}{3} (9)^{2} + 6 (9) + 1

16 \div 4 \times (3 - 1)

(- 36 + 18) + (- 42)

3 \times (3 + 4)

What is (1+5/3)\times (-8)\div 7 ?
The solution to (1+5/3)\times (-8)\div 7 is -64/21