What is 6/17 (5-4)^2 ?

The solution to 6/17 (5-4)^2 is 6/17

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6/17 (5-4)^2

\frac{6}{17} (5 - 4)^{2}

\frac{6}{17}

Solution steps

\frac{6}{17} (5 - 4)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 4) : 1

5 - 4

5 - 4 = 1

= 1

= \frac{6}{17} \cdot 1^{2}

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= \frac{6}{17} \cdot 1

Multiply and divide (left to right)

\frac{6}{17} \cdot 1 : \frac{6}{17}

\frac{6}{17} \cdot 1

\frac{6}{17} \cdot 1 = \frac{6}{17}

= \frac{6}{17}

= \frac{6}{17}

(12 + 15) - (3 + 2 + 1) - 4 - (1 + 2 - 6 + 7)

(- 3) + (- 1) + (+ 4) + (+ 2)

\frac{1}{2} (3)^{2}

4^{2} + 2

2 \times 3^{0}