What is (2-3)[[4(-2)+1]+1]+1 ?

The solution to (2-3)[[4(-2)+1]+1]+1 is 7

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(2-3)[[4(-2)+1]+1]+1

(2 - 3) [[4 (- 2) + 1] + 1] + 1

7

Solution steps

(2 - 3) [[4 (- 2) + 1] + 1] + 1

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - 3) : - 1

= - 1 \cdot [[4 (- 2) + 1] + 1] + 1

Calculate within parentheses

[[4 (- 2) + 1] + 1] : - 6

= - 1 \cdot (- 6) + 1

Multiply and divide (left to right)

- 1 \cdot (- 6) : 6

= 6 + 1

Add and subtract (left to right)

6 + 1 : 7

= 7

3 + 6 \div 2 - 5

\frac{( 1 5 ^{3} 3 0 ^{2} 1 8 ^{2} )}{( 9 ^{3} 1 2 ^{4} 5 ^{6} )}

2 (- 5) - 5 - 3^{2}

(2^{3} \times 3^{4})^{5}

11 - 48 \div (8 - 6) 2