What is 1/2 (2/1)^2 ?

The solution to 1/2 (2/1)^2 is 2

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1/2 (2/1)^2

\frac{1}{2} (\frac{2}{1})^{2}

2

Solution steps

\frac{1}{2} (\frac{2}{1})^{2}

\frac{2}{1} = 2

Apply rule

\frac{a}{1} = a

2

= \frac{1}{2} \cdot 2^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= \frac{1}{2} \cdot 4

Multiply and divide (left to right)

\frac{1}{2} \cdot 4 : 2

\frac{1}{2} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= \frac{1}{2} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 4}{2 \cdot 1}

\frac{1 \cdot 4}{2 \cdot 1} = 2

\frac{1 \cdot 4}{2 \cdot 1}

\frac{1 \cdot 4}{2 \cdot 1} = \frac{4}{2}

\frac{1 \cdot 4}{2 \cdot 1}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{4}{2}

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2

= 2

3 (- 2)^{2} - 4 (- 2) + 2

4 \cdot 1 + 9^{2}

- 2 \times [- 3 (5 + 4 - 3 - 6) - (2 + 4 + 8 - 9)] + 7

1 - (0)^{2}

\frac{( - 6 ) ^{13}}{( - 6 ) ^{5}}