What is (-1+2)(-1^2-2(-1)+4) ?

The solution to (-1+2)(-1^2-2(-1)+4) is 5

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(-1+2)(-1^2-2(-1)+4)

(- 1 + 2) (- 1^{2} - 2 (- 1) + 4)

5

Solution steps

(- 1 + 2) (- 1^{2} - 2 (- 1) + 4)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 1 + 2) : 1

= 1 \cdot (- 1^{2} - 2 (- 1) + 4)

Calculate within parentheses

(- 1^{2} - 2 (- 1) + 4) : 5

= 1 \cdot 5

Multiply and divide (left to right)

1 \cdot 5 : 5

= 5

- 7 + 19 - 23 - 14 + 5

(2 \div \frac{2}{3}) - (\frac{2}{3} \div 2)

- \frac{1}{3} + 3 \div 2

7 - \frac{2}{3} - \frac{1}{2}

18 + [9 - (- 3) + 5]