What is (1 1/9)\div (4-2 1/3) ?

The solution to (1 1/9)\div (4-2 1/3) is 2/3

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(1 1/9)\div (4-2 1/3)

(1 \frac{1}{9}) \div (4 - 2 \frac{1}{3})

\frac{2}{3}

Solution steps

(1 \frac{1}{9}) \div (4 - 2 \frac{1}{3})

Convert mixed numbers to improper fractions:

1 \frac{1}{9} = \frac{10}{9}

= (\frac{10}{9}) \div (4 - 2 \frac{1}{3})

Convert mixed numbers to improper fractions:

2 \frac{1}{3} = \frac{7}{3}

= (\frac{10}{9}) \div (4 - \frac{7}{3})

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - \frac{7}{3}) : \frac{5}{3}

= (\frac{10}{9}) \div \frac{5}{3}

Multiply and divide (left to right)

(\frac{10}{9}) \div \frac{5}{3} : \frac{( \frac{10}{9} )}{\frac{5}{3}}

= \frac{( \frac{10}{9} )}{\frac{5}{3}}

Simplify

\frac{( \frac{10}{9} )}{\frac{5}{3}} : \frac{2}{3}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{10 \cdot 3}{9 \cdot 5}

Multiply the numbers:

9 \cdot 5 = 45

= \frac{10 \cdot 3}{45}

Multiply the numbers:

10 \cdot 3 = 30

= \frac{30}{45}

Cancel the common factor:

15

= \frac{2}{3}

5^{2} + 4

- 8 - (- 11) + 17

(2)^{2} - 3

16 - 3 (8 - 3)^{2} \div 5

(- 2)^{2} - 2 (- 2)