What is 2^2-(2\times 2)+8 ?

The solution to 2^2-(2\times 2)+8 is 8

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2^2-(2\times 2)+8

2^{2} - (2 \cdot 2) + 8

8

Solution steps

2^{2} - (2 \cdot 2) + 8

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \cdot 2) : 4

= 2^{2} - 4 + 8

Calculate exponents

2^{2} : 4

= 4 - 4 + 8

Add and subtract (left to right)

4 - 4 + 8 : 8

= 8

3 \cdot 1 - 4

- 1^{2} - (- 1)^{2}

1 + 4 - 2 - 6 + 9 - 2 \times (- 4)

- 3 + 7 - 5

11 \times (- 9 - 10) + 8 (72 \div 12) - 7