What is 3^8-3^2\times 2^2+23^2 ?

The solution to 3^8-3^2\times 2^2+23^2 is 7054

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3^8-3^2\times 2^2+23^2

3^{8} - 3^{2} \cdot 2^{2} + 2 3^{2}

7054

Solution steps

3^{8} - 3^{2} \cdot 2^{2} + 2 3^{2}

Follow the PEMDAS order of operations

Calculate exponents

3^{8} : 6561

= 6561 - 3^{2} \cdot 2^{2} + 2 3^{2}

Calculate exponents

3^{2} : 9

= 6561 - 9 \cdot 2^{2} + 2 3^{2}

Calculate exponents

2^{2} : 4

= 6561 - 9 \cdot 4 + 2 3^{2}

Calculate exponents

2 3^{2} : 529

= 6561 - 9 \cdot 4 + 529

Multiply and divide (left to right)

9 \cdot 4 : 36

= 6561 - 36 + 529

Add and subtract (left to right)

6561 - 36 + 529 : 7054

= 7054

- 6 (- 3)^{2} + 2 (- 3) - 3

5/6 - (5/9) / (4/5)

1.66667

t o a p erce n t a g e 13/15

t o a p erce n t a g e 32/40