What is longmult 24*15 ?

The solution to longmult 24*15 is 360

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Multiply 24*15

long multiplication

24 \cdot 15

360

Solution steps

24 \cdot 15

Line up the numbers

\times 2145

Multiply the top number by the bottom number one digit at a time starting with the ones digit (from right to left)

Multiply the top number by the bolded digit of the bottom number

\times 2145

Mutliply the bold numbers:

4 \cdot 5 = 20

Carry

2

to the column on the left and write

0

in the result line

\frac{\times 2 2 1 4 5}{0}

Add the carried number to the multiplication:

2 + 2 \cdot 5 = 12

Carry

1

to the column on the left and write

2

in the result line

\frac{\times 1 2 2 1 4 5}{2 0}

Add the carried digit,

1

, to the result

\frac{\times 1 2 2 1 4 5}{1 2 0}

Multiply the top number by the bolded digit of the bottom number

\frac{\times 2 1 4 5}{1 2 0}

Mutliply the bold numbers:

4 \cdot 1 = 4

\frac{\times 2 1 4 5}{1 2 4 0}

Mutliply the bold numbers:

2 \cdot 1 = 2

\frac{\times 2 1 4 5}{1 2 2 4 0}

Add the rows to get the answer. For simplicity, fill in trailing zeros

\frac{\times 2 1 4 5}{1 2 2 4 0 0}

120 + 240 = 360

+ 122400

Add the digits of the bolded column:

0 + 0 = 0

\frac{+ 1 2 2 4 0 0}{+ 0}

Add the digits of the bolded column:

2 + 4 = 6

\frac{+ 1 2 2 4 0 0}{+ 6 0}

Add the digits of the bolded column:

1 + 2 = 3

\frac{+ 1 2 2 4 0 0}{+ 3 6 0}

= 360

= 360

\frac{4500}{12}

\frac{13}{4}

t h e \frac{80}{180}

\frac{100}{11}

t h e \frac{140}{360}