What is 23-(17-3*4)^2+6 ?

The solution to 23-(17-3*4)^2+6 is 4

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23-(17-3*4)^2+6

23 - (17 - 3 \cdot 4)^{2} + 6

4

Solution steps

23 - (17 - 3 \cdot 4)^{2} + 6

Follow the PEMDAS order of operations

Calculate within parentheses

(17 - 3 \cdot 4) : 5

17 - 3 \cdot 4

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= 17 - 12

Add and subtract (left to right)

17 - 12 : 5

17 - 12

17 - 12 = 5

= 5

= 5

= 23 - 5^{2} + 6

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 23 - 25 + 6

Add and subtract (left to right)

23 - 25 + 6 : 4

23 - 25 + 6

23 - 25 = - 2

= - 2 + 6

- 2 + 6 = 4

= 4

= 4

\frac{63}{18}

40, 60, 100

\frac{12}{1.5}

4.9

ro u n d t o t h e n e a res t h u n d re d t h 43.96