What is 440-(30+6(19-12)) ?

The solution to 440-(30+6(19-12)) is 368

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440-(30+6(19-12))

440 - (30 + 6 (19 - 12))

368

Solution steps

440 - (30 + 6 (19 - 12))

Follow the PEMDAS order of operations

Calculate within parentheses

(30 + 6 (19 - 12)) : 72

= 440 - 72

Add and subtract (left to right)

440 - 72 : 368

= 368

- (- (8 - 19) - 25) + (- (- 50 + 40 - 15))

6 \cdot 5^{2}

3 - [(3 - 4) + 5 - (7 + 8) - (15 - 14) + (7 - 8)]

4 \frac{1}{2} + (\frac{3}{5} - \frac{1}{6})

3^{4} + 3^{2}