What is [-3-(-12)]-(40-12)+3-(-15) ?

The solution to [-3-(-12)]-(40-12)+3-(-15) is -1

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[-3-(-12)]-(40-12)+3-(-15)

[- 3 - (- 12)] - (40 - 12) + 3 - (- 15)

- 1

Solution steps

[- 3 - (- 12)] - (40 - 12) + 3 - (- 15)

Follow the PEMDAS order of operations

Calculate within parentheses

[- 3 - (- 12)] : 9

= 9 - (40 - 12) + 3 - (- 15)

Calculate within parentheses

(40 - 12) : 28

= 9 - 28 + 3 - (- 15)

Add and subtract (left to right)

9 - 28 + 3 - (- 15) : - 1

= - 1

4 - 8 + 3

9 \div 3 - (- 12) \div 2 - 13 \div (- 1)

- 5 + 4 \cdot 10 \div 2 \cdot 1 - 5

8 - 4 (7 - 3 \times 4) - 2 (6 - 3 \times 2) + 6 - 8

8^{2} + 1 4^{2}

What is [-3-(-12)]-(40-12)+3-(-15) ?
The solution to [-3-(-12)]-(40-12)+3-(-15) is -1