What is 11^2-(7+5-9)^2+12-(33+2) ?

The solution to 11^2-(7+5-9)^2+12-(33+2) is 89

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11^2-(7+5-9)^2+12-(33+2)

1 1^{2} - (7 + 5 - 9)^{2} + 12 - (33 + 2)

89

Solution steps

1 1^{2} - (7 + 5 - 9)^{2} + 12 - (33 + 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(7 + 5 - 9) : 3

= 1 1^{2} - 3^{2} + 12 - (33 + 2)

Calculate within parentheses

(33 + 2) : 35

= 1 1^{2} - 3^{2} + 12 - 35

Calculate exponents

1 1^{2} : 121

= 121 - 3^{2} + 12 - 35

Calculate exponents

3^{2} : 9

= 121 - 9 + 12 - 35

Add and subtract (left to right)

121 - 9 + 12 - 35 : 89

= 89

(13 - 8)^{3}

5 + (\frac{3}{4} - \frac{1}{2}) \div 2

20 - (- 45) \div (- 3)^{2} + (- 2) \times (- 1)^{5}

(- 4 + 2)^{2}

27 \times 2 + (32 + 16 \times 4) \times 3

What is 11^2-(7+5-9)^2+12-(33+2) ?
The solution to 11^2-(7+5-9)^2+12-(33+2) is 89