What is 5(4-2)^2+1^2(2^3-5)^2 ?

The solution to 5(4-2)^2+1^2(2^3-5)^2 is 29

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5(4-2)^2+1^2(2^3-5)^2

5 (4 - 2)^{2} + 1^{2} (2^{3} - 5)^{2}

29

Solution steps

5 (4 - 2)^{2} + 1^{2} (2^{3} - 5)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 2) : 2

= 5 \cdot 2^{2} + 1^{2} (2^{3} - 5)^{2}

Calculate within parentheses

(2^{3} - 5) : 3

= 5 \cdot 2^{2} + 1^{2} \cdot 3^{2}

Calculate exponents

2^{2} : 4

= 5 \cdot 4 + 1^{2} \cdot 3^{2}

Calculate exponents

1^{2} : 1

= 5 \cdot 4 + 1 \cdot 3^{2}

Calculate exponents

3^{2} : 9

= 5 \cdot 4 + 1 \cdot 9

Multiply and divide (left to right)

5 \cdot 4 : 20

= 20 + 1 \cdot 9

Multiply and divide (left to right)

1 \cdot 9 : 9

= 20 + 9

Add and subtract (left to right)

20 + 9 : 29

= 29

\frac{120}{4}

7 \cdot (6 + 2)^{2} - 3^{2}

2 - 3 + (- 5) + (- 3)

\frac{216}{3}

\frac{128}{4}