What is -2^4-(-2)^4+(-2)^2 ?

The solution to -2^4-(-2)^4+(-2)^2 is -28

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-2^4-(-2)^4+(-2)^2

- 2^{4} - (- 2)^{4} + (- 2)^{2}

- 28

Solution steps

- 2^{4} - (- 2)^{4} + (- 2)^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= - 16 - (- 2)^{4} + (- 2)^{2}

Calculate exponents

(- 2)^{4} : 16

(- 2)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{4} = 2^{4} = 16

= 16

= - 16 - 16 + (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 16 - 16 + 4

Add and subtract (left to right)

- 16 - 16 + 4 : - 28

- 16 - 16 + 4

- 16 - 16 = - 32

= - 32 + 4

- 32 + 4 = - 28

= - 28

= - 28

(2^{4} - 3 \times 4) \div 2 + 50 \div 5^{2}

3 (- 3)^{2} - 3 (- 3)

(- 3 - 1)^{2}

- 2^{2} + 6

5 0^{2} - 4 0^{2}