What is (2+5)^2-((-2)^3-((3)(4)-(8\div 2))) ?

The solution to (2+5)^2-((-2)^3-((3)(4)-(8\div 2))) is 65

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(2+5)^2-((-2)^3-((3)(4)-(8\div 2)))

(2 + 5)^{2} - ((- 2)^{3} - ((3) (4) - (8 \div 2)))

65

Solution steps

(2 + 5)^{2} - ((- 2)^{3} - ((3) (4) - (8 \div 2)))

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 5) : 7

2 + 5

2 + 5 = 7

= 7

= 7^{2} - ((- 2)^{3} - ((3) (4) - (8 \div 2)))

Calculate within parentheses

((- 2)^{3} - ((3) (4) - (8 \div 2))) : - 16

(- 2)^{3} - ((3) (4) - (8 \div 2))

Calculate within parentheses

((3) (4) - (8 \div 2)) : 8

(3) (4) - (8 \div 2)

Calculate within parentheses

(8 \div 2) : 4

8 \div 2

8 \div 2 = 4

= 4

= (3) (4) - 4

Multiply and divide (left to right)

(3) (4) : 12

(3) (4)

(3) (4) = 3 \cdot 4

(3) (4)

Apply rule:

(a) = a

(3) = 3

= 3 (4)

Apply rule:

(a) = a

(4) = 4

= 3 \cdot 4

= 3 \cdot 4

Multiply the numbers:

3 \cdot 4 = 12

= 12

= 12 - 4

Add and subtract (left to right)

12 - 4 : 8

12 - 4

12 - 4 = 8

= 8

= 8

= (- 2)^{3} - 8

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 - 8

Add and subtract (left to right)

- 8 - 8 : - 16

- 8 - 8

- 8 - 8 = - 16

= - 16

= - 16

= 7^{2} - (- 16)

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 49 - (- 16)

Add and subtract (left to right)

49 - (- 16) : 65

49 - (- 16)

Apply rule

- (- a) = + a

- (- 16) = + 16

= 49 + 16

49 + 16 = 65

= 65

= 65

3 (- 2)^{2} + 6 (- 2) - 9

\frac{( 9 ^{2} - 17 )}{2 ^{2}}

- 2 (- 2) + 4

(- 3 - 5) \div (- 4)

2^{2} - 2^{3}

What is (2+5)^2-((-2)^3-((3)(4)-(8\div 2))) ?
The solution to (2+5)^2-((-2)^3-((3)(4)-(8\div 2))) is 65