What is -4/3 (2+1/4) ?

The solution to -4/3 (2+1/4) is -3

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-4/3 (2+1/4)

- \frac{4}{3} (2 + \frac{1}{4})

- 3

Solution steps

- \frac{4}{3} (2 + \frac{1}{4})

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + \frac{1}{4}) : \frac{9}{4}

2 + \frac{1}{4}

2 + \frac{1}{4} = \frac{9}{4}

2 + \frac{1}{4}

Convert element to fraction:

2 = \frac{2 \cdot 4}{4}

= \frac{2 \cdot 4}{4} + \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 4 + 1}{4}

2 \cdot 4 + 1 = 9

2 \cdot 4 + 1

Multiply the numbers:

2 \cdot 4 = 8

= 8 + 1

Add the numbers:

8 + 1 = 9

= 9

= \frac{9}{4}

= \frac{9}{4}

= - \frac{4}{3} \cdot \frac{9}{4}

Multiply and divide (left to right)

- \frac{4}{3} \cdot \frac{9}{4} : - 3

- \frac{4}{3} \cdot \frac{9}{4}

Cross-cancel common factor:

4

= - \frac{9}{3}

Divide the numbers:

\frac{9}{3} = 3

= - 3

= - 3

5^{2} + 3^{3}

2 \frac{1}{3} - (\frac{1}{3} + \frac{7}{15})

1^{3} + 2 \times 1^{2} + 1

2^{12} - 2

9^{2} \div (2 \times 6 - 3)