What is ((6^2-3^3))/2 ?

The solution to ((6^2-3^3))/2 is 4 1/2

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((6^2-3^3))/2

\frac{( 6 ^{2} - 3 ^{3} )}{2}

4 \frac{1}{2}

Solution steps

\frac{( 6 ^{2} - 3 ^{3} )}{2}

Solve

(6^{2} - 3^{3}) : 9

Follow the PEMDAS order of operations

Calculate within parentheses

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= 36 - 3^{3}

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 36 - 27

Add and subtract (left to right)

36 - 27 : 9

36 - 27

36 - 27 = 9

= 9

= 9

= \frac{9}{2}

Convert improper fractions to mixed numbers:

\frac{9}{2} = 4 \frac{1}{2}

\frac{9}{2} = 4

Remainder

1

\frac{9}{2}

Write the problem in long division format

2 \overline{∣ 9}

Divide

9

2

to get

4

Divide

9

2

to get

4

4 2 \overline{∣ 9}

Multiply the quotient digit

(4)

by the divisor

2

4 2 \overline{∣ 9} \underline{8}

Subtract

8

from

9

4 2 \overline{∣ 9} \underline{8} 1

4 2 \overline{∣ 9} \underline{8} 1

The solution for Long Division of

\frac{9}{2}

4

with remainder of

1

4 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{9}{2} = 4 \frac{1}{2}

= 4 \frac{1}{2}

= 4 \frac{1}{2}

\frac{14}{7} \cdot 5 - 3^{2}

(- 45) - \frac{( - 49 )}{7} \cdot (- 6)

\frac{0.5}{2}

\frac{112}{2}

1 - 3 - 5 - 7 + 5 - 8 - 2 + 4