What is 2*16/41+5*25/41 ?

The solution to 2*16/41+5*25/41 is 3 34/41

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Popular >

216/41+525/41

Solution

2 \cdot \frac{16}{41} + 5 \cdot \frac{25}{41}

Solution

3 \frac{34}{41}

Solution steps

2 \cdot \frac{16}{41} + 5 \cdot \frac{25}{41}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

2 \cdot \frac{16}{41} : \frac{32}{41}

2 \cdot \frac{16}{41}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{16}{41}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 16}{1 \cdot 41}

Multiply the numbers:

2 \cdot 16 = 32

= \frac{32}{1 \cdot 41}

Multiply the numbers:

1 \cdot 41 = 41

= \frac{32}{41}

= \frac{32}{41} + 5 \cdot \frac{25}{41}

Multiply and divide (left to right)

5 \cdot \frac{25}{41} : \frac{125}{41}

5 \cdot \frac{25}{41}

Convert element to fraction:

5 = \frac{5}{1}

= \frac{5}{1} \cdot \frac{25}{41}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 \cdot 25}{1 \cdot 41}

Multiply the numbers:

5 \cdot 25 = 125

= \frac{125}{1 \cdot 41}

Multiply the numbers:

1 \cdot 41 = 41

= \frac{125}{41}

= \frac{32}{41} + \frac{125}{41}

Add and subtract (left to right)

\frac{32}{41} + \frac{125}{41} : \frac{157}{41}

\frac{32}{41} + \frac{125}{41}

\frac{32}{41} + \frac{125}{41} = \frac{157}{41}

\frac{32}{41} + \frac{125}{41}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{32 + 125}{41}

Add the numbers:

32 + 125 = 157

= \frac{157}{41}

= \frac{157}{41}

= \frac{157}{41}

Convert improper fractions to mixed numbers:

\frac{157}{41} = 3 \frac{34}{41}

\frac{157}{41} = 3

Remainder

34

\frac{157}{41}

Write the problem in long division format

41 \overline{∣ 157}

Divide

157

41

to get

3

Divide

157

41

to get

3

3 41 \overline{∣ 157}

Multiply the quotient digit

(3)

by the divisor

41

3 41 \overline{∣ 157} \underline{123}

Subtract

123

from

157

3 41 \overline{∣ 157} \underline{123} 34

3 41 \overline{∣ 157} \underline{123} 34

The solution for Long Division of

\frac{157}{41}

3

with remainder of

34

3 Remainder 34

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{157}{41} = 3 \frac{34}{41}

= 3 \frac{34}{41}

= 3 \frac{34}{41}

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8(2)^2-11

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Frequently Asked Questions (FAQ)

What is 2*16/41+5*25/41 ?
The solution to 2*16/41+5*25/41 is 3 34/41