What is (3-5)^2+4(3-1)-3(1+1)^2(2)+2(3)(2) ?

The solution to (3-5)^2+4(3-1)-3(1+1)^2(2)+2(3)(2) is 0

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(3-5)^2+4(3-1)-3(1+1)^2(2)+2(3)(2)

(3 - 5)^{2} + 4 (3 - 1) - 3 (1 + 1)^{2} (2) + 2 (3) (2)

0

Solution steps

(3 - 5)^{2} + 4 (3 - 1) - 3 (1 + 1)^{2} (2) + 2 (3) (2)

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 5) : - 2

3 - 5

3 - 5 = - 2

= - 2

= (- 2)^{2} + 4 (3 - 1) - 3 (1 + 1)^{2} (2) + 2 (3) (2)

Calculate within parentheses

(3 - 1) : 2

3 - 1

3 - 1 = 2

= 2

= (- 2)^{2} + 4 \cdot 2 - 3 (1 + 1)^{2} (2) + 2 (3) (2)

Calculate within parentheses

(1 + 1) : 2

1 + 1

1 + 1 = 2

= 2

= (- 2)^{2} + 4 \cdot 2 - 3 \cdot 2^{2} (2) + 2 (3) (2)

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 4 \cdot 2 - 3 \cdot 2^{2} (2) + 2 (3) (2)

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 + 4 \cdot 2 - 3 \cdot 4 (2) + 2 (3) (2)

Multiply and divide (left to right)

4 \cdot 2 : 8

4 \cdot 2

4 \cdot 2 = 8

= 8

= 4 + 8 - 3 \cdot 4 (2) + 2 (3) (2)

Multiply and divide (left to right)

3 \cdot 4 (2) : 24

3 \cdot 4 (2)

3 \cdot 4 = 12

= 12 (2)

12 (2) = 24

12 (2)

Apply rule:

(a) = a

(2) = 2

= 12 \cdot 2

Multiply the numbers:

12 \cdot 2 = 24

= 24

= 24

= 4 + 8 - 24 + 2 (3) (2)

Multiply and divide (left to right)

2 (3) (2) : 12

2 (3) (2)

2 (3) = 6

2 (3)

Apply rule:

(a) = a

(3) = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= 6 (2)

6 (2) = 12

6 (2)

Apply rule:

(a) = a

(2) = 2

= 6 \cdot 2

Multiply the numbers:

6 \cdot 2 = 12

= 12

= 12

= 4 + 8 - 24 + 12

Add and subtract (left to right)

4 + 8 - 24 + 12 : 0

4 + 8 - 24 + 12

4 + 8 = 12

= 12 - 24 + 12

12 - 24 = - 12

= - 12 + 12

- 12 + 12 = 0

= 0

= 0

- 9 (- 1)^{2}

2 \cdot 1 - 5

3 (7)^{2} - 30 (7) + 72

2 \cdot 2 - 4

1 4^{2} + 6^{2}

What is (3-5)^2+4(3-1)-3(1+1)^2(2)+2(3)(2) ?
The solution to (3-5)^2+4(3-1)-3(1+1)^2(2)+2(3)(2) is 0