What is 10-2+(-3-4)-1-(-5) ?

The solution to 10-2+(-3-4)-1-(-5) is 5

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10-2+(-3-4)-1-(-5)

10 - 2 + (- 3 - 4) - 1 - (- 5)

5

Solution steps

10 - 2 + (- 3 - 4) - 1 - (- 5)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 3 - 4) : - 7

- 3 - 4

- 3 - 4 = - 7

= - 7

= 10 - 2 - 7 - 1 - (- 5)

Add and subtract (left to right)

10 - 2 - 7 - 1 - (- 5) : 5

10 - 2 - 7 - 1 - (- 5)

10 - 2 = 8

= 8 - 7 - 1 - (- 5)

8 - 7 = 1

= 1 - 1 - (- 5)

1 - 1 = 0

= 0 - (- 5)

Apply rule

- (- a) = + a

- (- 5) = + 5

= 0 + 5

0 + 5 = 5

= 5

= 5

2 \times (- 3 + 6) - 5 \times (- 4 + 3)

7^{2} - 3^{2} \times 4

- 3 (2) + 2

\frac{( 18 - 2 ) 180}{18}

5 (- 4 - 5)^{2} + 10