What is 80\div [25-(+3)+(+2)+(+2)] ?

The solution to 80\div [25-(+3)+(+2)+(+2)] is 3 1/13

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80\div [25-(+3)+(+2)+(+2)]

80 \div [25 - (+ 3) + (+ 2) + (+ 2)]

3 \frac{1}{13}

Solution steps

80 \div [25 - (3) + (2) + (2)]

Follow the PEMDAS order of operations

Calculate within parentheses

[25 - (3) + (2) + (2)] : 26

= 80 \div 26

Multiply and divide (left to right)

80 \div 26 : \frac{80}{26}

= \frac{80}{26}

Simplify

\frac{80}{26} : 3 \frac{1}{13}

Cancel the common factor:

2

= \frac{40}{13}

Convert improper fractions to mixed numbers:

\frac{40}{13} = 3 \frac{1}{13}

= 3 \frac{1}{13}

- 6 - 10 - 3 + 12 + 13 + 14

5 - (- 1)^{2}

\frac{1}{3} (4)^{3}

- 22 - 8 + 4^{3} + 14

1 2^{2} - 5^{2}

What is 80\div [25-(+3)+(+2)+(+2)] ?
The solution to 80\div [25-(+3)+(+2)+(+2)] is 3 1/13