What is (2*6)-7+9^2+45/5 ?

The solution to (2*6)-7+9^2+45/5 is 95

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(2*6)-7+9^2+45/5

(2 \cdot 6) - 7 + 9^{2} + \frac{45}{5}

95

Solution steps

(2 \cdot 6) - 7 + 9^{2} + \frac{45}{5}

\frac{45}{5} = 9

Divide the numbers:

\frac{45}{5} = 9

9

= 2 \cdot 6 - 7 + 9^{2} + 9

Follow the PEMDAS order of operations

Calculate exponents

9^{2} : 81

9^{2}

9^{2} = 81

= 81

= 2 \cdot 6 - 7 + 81 + 9

Multiply and divide (left to right)

2 \cdot 6 : 12

2 \cdot 6

2 \cdot 6 = 12

= 12

= 12 - 7 + 81 + 9

Add and subtract (left to right)

12 - 7 + 81 + 9 : 95

12 - 7 + 81 + 9

12 - 7 = 5

= 5 + 81 + 9

5 + 81 = 86

= 86 + 9

86 + 9 = 95

= 95

= 95

(- 3)^{3} - 4^{2}

6 + 2 - (- 1) + (- 8)

4 - (3 - 2)^{2}

3^{3} - 10 + 7

2 4^{2} + 7^{2}