The solution to (2-3)^2-4 is -3

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(2-3)^2-4

Solution

(2 - 3)^{2} - 4

- 3

Solution steps

(2 - 3)^{2} - 4

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - 3) : - 1

2 - 3

2 - 3 = - 1

= - 1

= (- 1)^{2} - 4

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 - 4

Add and subtract (left to right)

1 - 4 : - 3

1 - 4

1 - 4 = - 3

= - 3

= - 3

- 9 + (- 8) + 15 - 17 - (- 32) + 0

6 \times 3 - (2 + 5 \times 2) + (5 \times 3 - 8) - 1

[8 \times (23 - 19)] \div 2

2^{0} - 2

2^{3} + [(8^{3} - 3^{3}) \cdot 1^{5}]