What is 4\div 9-1\div 9 ?

The solution to 4\div 9-1\div 9 is 1/3

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4\div 9-1\div 9

4 \div 9 - 1 \div 9

\frac{1}{3}

Solution steps

4 \div 9 - 1 \div 9

Follow the PEMDAS order of operations

Multiply and divide (left to right)

4 \div 9 : \frac{4}{9}

4 \div 9

4 \div 9 = \frac{4}{9}

= \frac{4}{9}

= \frac{4}{9} - 1 \div 9

Multiply and divide (left to right)

1 \div 9 : \frac{1}{9}

1 \div 9

1 \div 9 = \frac{1}{9}

= \frac{1}{9}

= \frac{4}{9} - \frac{1}{9}

Add and subtract (left to right)

\frac{4}{9} - \frac{1}{9} : \frac{1}{3}

\frac{4}{9} - \frac{1}{9}

\frac{4}{9} - \frac{1}{9} = \frac{1}{3}

\frac{4}{9} - \frac{1}{9}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 - 1}{9}

Subtract the numbers:

4 - 1 = 3

= \frac{3}{9}

Cancel the common factor:

3

= \frac{1}{3}

= \frac{1}{3}

= \frac{1}{3}

(- 9) - (- 8) + 2 \times 4^{2}

\frac{1}{2} (2) + 1

\frac{1}{2} \cdot 4^{0}

(2 + 3)^{3}

(9)^{2} - 30 (9) + 200