What is 4+45/35-5+15/35 ?

The solution to 4+45/35-5+15/35 is 5/7

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4+45/35-5+15/35

4 + \frac{45}{35} - 5 + \frac{15}{35}

\frac{5}{7}

Solution steps

4 + \frac{45}{35} - 5 + \frac{15}{35}

\frac{45}{35} = \frac{9}{7}

Cancel the common factor:

5

\frac{9}{7}

= 4 + \frac{9}{7} - 5 + \frac{15}{35}

\frac{15}{35} = \frac{3}{7}

Cancel the common factor:

5

\frac{3}{7}

= 4 + \frac{9}{7} - 5 + \frac{3}{7}

Follow the PEMDAS order of operations

Add and subtract (left to right)

4 + \frac{9}{7} - 5 + \frac{3}{7} : \frac{5}{7}

4 + \frac{9}{7} - 5 + \frac{3}{7}

4 + \frac{9}{7} = \frac{37}{7}

4 + \frac{9}{7}

Convert element to fraction:

4 = \frac{4 \cdot 7}{7}

= \frac{4 \cdot 7}{7} + \frac{9}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 7 + 9}{7}

4 \cdot 7 + 9 = 37

4 \cdot 7 + 9

Multiply the numbers:

4 \cdot 7 = 28

= 28 + 9

Add the numbers:

28 + 9 = 37

= 37

= \frac{37}{7}

= \frac{37}{7} - 5 + \frac{3}{7}

\frac{37}{7} - 5 = \frac{2}{7}

\frac{37}{7} - 5

Convert element to fraction:

5 = \frac{5 \cdot 7}{7}

= - \frac{5 \cdot 7}{7} + \frac{37}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 5 \cdot 7 + 37}{7}

- 5 \cdot 7 + 37 = 2

- 5 \cdot 7 + 37

Multiply the numbers:

5 \cdot 7 = 35

= - 35 + 37

Add/Subtract the numbers:

- 35 + 37 = 2

= 2

= \frac{2}{7}

= \frac{2}{7} + \frac{3}{7}

\frac{2}{7} + \frac{3}{7} = \frac{5}{7}

\frac{2}{7} + \frac{3}{7}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 3}{7}

Add the numbers:

2 + 3 = 5

= \frac{5}{7}

= \frac{5}{7}

= \frac{5}{7}

1 0^{5} \div 5^{10}

(2^{4} \times 3^{4} \times 6^{4}) + 5^{0}

4 \times 3 - 2^{2} \times 4 + 7 - 3

25 + 10 - 75 - 8 + 35 - 7

\frac{1 ^{2} - 1}{1 + 1}