What is 7 7/8+(3 1/8+1 1/8) ?

The solution to 7 7/8+(3 1/8+1 1/8) is 12 1/8

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7 7/8+(3 1/8+1 1/8)

7 \frac{7}{8} + (3 \frac{1}{8} + 1 \frac{1}{8})

12 \frac{1}{8}

Solution steps

7 \frac{7}{8} + (3 \frac{1}{8} + 1 \frac{1}{8})

Convert mixed numbers to improper fractions:

7 \frac{7}{8} = \frac{63}{8}

= \frac{63}{8} + (3 \frac{1}{8} + 1 \frac{1}{8})

Convert mixed numbers to improper fractions:

3 \frac{1}{8} = \frac{25}{8}

= \frac{63}{8} + (\frac{25}{8} + 1 \frac{1}{8})

Convert mixed numbers to improper fractions:

1 \frac{1}{8} = \frac{9}{8}

= \frac{63}{8} + (\frac{25}{8} + \frac{9}{8})

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{25}{8} + \frac{9}{8}) : \frac{17}{4}

= \frac{63}{8} + \frac{17}{4}

Add and subtract (left to right)

\frac{63}{8} + \frac{17}{4} : \frac{97}{8}

= \frac{97}{8}

Convert improper fractions to mixed numbers:

\frac{97}{8} = 12 \frac{1}{8}

= 12 \frac{1}{8}

\frac{1}{2} (- 3)^{2}

- 14 + 82 - 67

\frac{2 ^{2} - 4 \cdot 2 \cdot ( - 5 )}{2 \cdot 1}

2 (3 + 2)

- 2 (0) - 1