What is (3-2)^5-7(1+4)^2+80 ?

The solution to (3-2)^5-7(1+4)^2+80 is -94

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(3-2)^5-7(1+4)^2+80

(3 - 2)^{5} - 7 (1 + 4)^{2} + 80

- 94

Solution steps

(3 - 2)^{5} - 7 (1 + 4)^{2} + 80

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 2) : 1

3 - 2

3 - 2 = 1

= 1

= 1^{5} - 7 (1 + 4)^{2} + 80

Calculate within parentheses

(1 + 4) : 5

1 + 4

1 + 4 = 5

= 5

= 1^{5} - 7 \cdot 5^{2} + 80

Calculate exponents

1^{5} : 1

1^{5}

1^{5} = 1

= 1

= 1 - 7 \cdot 5^{2} + 80

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 1 - 7 \cdot 25 + 80

Multiply and divide (left to right)

7 \cdot 25 : 175

7 \cdot 25

7 \cdot 25 = 175

= 175

= 1 - 175 + 80

Add and subtract (left to right)

1 - 175 + 80 : - 94

1 - 175 + 80

1 - 175 = - 174

= - 174 + 80

- 174 + 80 = - 94

= - 94

= - 94

0.75

10 - 9 \cdot (- 6)

- 8 - (- 10)^{2}

\frac{1}{2.5}

- 8 - (- 2) (5)