What is -32-5(7-10)^2 ?

The solution to -32-5(7-10)^2 is -77

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-32-5(7-10)^2

- 32 - 5 (7 - 10)^{2}

- 77

Solution steps

- 32 - 5 (7 - 10)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(7 - 10) : - 3

7 - 10

7 - 10 = - 3

= - 3

= - 32 - 5 (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 32 - 5 \cdot 9

Multiply and divide (left to right)

5 \cdot 9 : 45

5 \cdot 9

5 \cdot 9 = 45

= 45

= - 32 - 45

Add and subtract (left to right)

- 32 - 45 : - 77

- 32 - 45

- 32 - 45 = - 77

= - 77

= - 77

- (- 1)^{2} + 2 (- 1)

(7 - 5)^{2}

8^{2} - 6^{3}

- 7 \frac{4}{5} + (- 2) \frac{1}{5}

\frac{- 9/27 + 1}{- 9/27}