What is 2^5-(4^2)/(2^2) ?

The solution to 2^5-(4^2)/(2^2) is 28

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simplify 2^5-(4^2)/(2^2)

simplify

2^{5} - \frac{4 ^{2}}{2 ^{2}}

28

Solution steps

2^{5} - \frac{4 ^{2}}{2 ^{2}}

2^{5} = 32

2^{5}

2^{5} = 32

= 32

\frac{4 ^{2}}{2 ^{2}} = 4

\frac{4 ^{2}}{2 ^{2}}

Factor

4^{2} : 2^{4}

4^{2}

Factor the number:

4 = 2^{2}

= (2^{2})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}, a \geq 0

= 2^{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= 2^{4}

= \frac{2 ^{4}}{2 ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= 2^{4 - 2}

Subtract the numbers:

4 - 2 = 2

= 2^{2}

2^{2} = 4

= 4

= 32 - 4

Subtract the numbers:

32 - 4 = 28

= 28

0.9

7^{2} - 5^{2}

13 \cdot 13

1.2

2 \cdot 1 0^{2}