What is -8^2+(6-9)^4 ?

The solution to -8^2+(6-9)^4 is 17

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-8^2+(6-9)^4

- 8^{2} + (6 - 9)^{4}

17

Solution steps

- 8^{2} + (6 - 9)^{4}

Follow the PEMDAS order of operations

Calculate within parentheses

(6 - 9) : - 3

6 - 9

6 - 9 = - 3

= - 3

= - 8^{2} + (- 3)^{4}

Calculate exponents

8^{2} : 64

8^{2}

8^{2} = 64

= 64

= - 64 + (- 3)^{4}

Calculate exponents

(- 3)^{4} : 81

(- 3)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{4} = 3^{4} = 81

= 81

= - 64 + 81

Add and subtract (left to right)

- 64 + 81 : 17

- 64 + 81

- 64 + 81 = 17

= 17

= 17

9^{10} + 9^{10} + 9^{10}

2 (6) + 3

0^{2} - 40 - 24 + 60

(1 \frac{1}{9}) + (4 - 2 \frac{1}{3})

\frac{1}{2} \cdot 5 (8 + 18)